> Isn't that just two db, since the decibel scale is logarithmic? <
The decibel scale is indeed log-based. But I think you've got your numbers wrong.
Here's the way I THINK it was taught to me, 40 years ago:
Three dB is an approximate doubling of power, and ten dB is approximately a ten-fold increase in power.
So a hundred-fold decrease would be a decrease of ca. 100 dB.
Almost. The first ten fold is 10 dB the second ten fold (10x10 = 100) is also 10 dB. So the total would be 20 dB.
However, the original article linked above indicated a 100 fold decrease in decibels which is quite significant. Who knows if the reporter got it right.
Database wrote:
> the original article linked above indicated a 100 fold decrease in decibels which is quite significant. Who knows if the reporter got it right. <
It's hard to imagine the reporter did get the facts right, because if my math is correct, a 100 dB decrease would be a decrease in power by a factor of 10,000,000,000!
(Ten raised to the tenth power.)
And I don't think even BATF would believe any muffler or silencer or suppressor could do that much!