To: dynoman
As I understand it he shell used in the IED did not produce much sarin because the binary components did not mix properly. Normally, the binary components mix prior to the dispersal detonation of the shell. There is normally an inner cavity where the components get sloshed together and mixed, with the resultant agent ready to be dispersed - also, the dispersion charge is small in order to not denature the agent. This design requirement is one of the reasons that binary rounds are so obviously different from conventional ones, even when empty.
100 posted on
06/22/2006 12:56:13 PM PDT by
lepton
("It is useless to attempt to reason a man out of a thing he was never reasoned into"--Jonathan Swift)
To: lepton
I just read Iraq was though to not posess binary shells, and that the he did produce looked exactly like normal shells.
Here in the comments section. I've read these same things other places too.
105 posted on
06/22/2006 1:05:08 PM PDT by
dynoman
(Objectivity is the essence of intelligence. - Marylin vos Savant)
FreeRepublic.com is powered by software copyright 2000-2008 John Robinson