To: King Prout
x**3-1=0 is the equation we need to solve. -1 is one solution.
(x**3-1)/(x-1)=x**2+x+1 so we solve this by the quadratic formula.
x=(-1+Sqrt(-3))/2 or (-1-Sqrt(-3))/2
These are the others cube roots. Multiplying by 3 gives the cube roots of (-27).
59 posted on
12/04/2005 10:12:43 AM PST by
Doctor Stochastic
(Vegetabilisch = chaotisch ist der Charakter der Modernen. - Friedrich Schlegel)
To: Doctor Stochastic
(x**3-1)/(x-1)=x**2+x+1 so we solve this by the quadratic formula.x=(-1+Sqrt(-3))/2 or (-1-Sqrt(-3))/2
These are the others cube roots. Multiplying by 3 gives the cube roots of (-27).
Does sqrt(-1) have two roots?
To: Doctor Stochastic
inquiry: does x**3 = x^3?
67 posted on
12/04/2005 10:31:33 AM PST by
King Prout
(many accuse me of being overly literal... this would not be a problem if many were not under-precise)
To: Doctor Stochastic
x**3-1=0 is the equation we need to solve. -1 is one solution.I thought we were discussing the cube root of negative one.
If this is so, wouldn't it be "x**3 + 1 = 0"?
72 posted on
12/04/2005 10:37:17 AM PST by
King Prout
(many accuse me of being overly literal... this would not be a problem if many were not under-precise)
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