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To: spunkets

You seem to be well versed in physics, thus someone I can have an intelligent conversation with. t=dKE=m in words is : time is delta kinetic energy is mass, either inertial or gravitational. Can we agree on that? Or as I say in my "time prize" offer : $1000 cash to the first person to demonstrate a time event that is NOT a kinetic energy event. In 20 years of asking, no winners yet... Ok then, do you know what MATTER WAVES are? No, NOT bose-photon electromagnetic waves, the waves that accompany every fermion; hidden, invisible MATTER WAVES, or the "wave function" that physicists often obliquely refer to. That's the next link in the chain. Also, why are the terms "delta momentum" and "rest mass" oxmorons?


132 posted on 10/03/2005 12:28:40 PM PDT by timer
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To: timer
" t=dKE=m in words is : time is delta kinetic energy is mass, either inertial or gravitational. Can we agree on that?"

I made a mistake in #128. 1/t=delta KE=m-m0. Time is a dimension. The meaning of the dimension is, "is", or "exists". Delta t means "it" exists for some time period. This equation says, "it = 1/energy." Potential E exists, but that is always dependent on the presence of KE.

KE was given in Einstein's paper as:

KE = m0( 1/sqrt(1-v2) - 1)

So KE is Etotal - Erest. If v=0, then KE=0. The rest E, is the field energy that ends up localized in space. It has a local frame. The Standard Model says interation the the field with the Higgs field is responsible for the mass. The localized E then has the property of mass. Given it exists in this universe, the particle will always have KE and PE. Since KE + PE of the universe is ~zero, the universe will exist for a very long time.

"why are the terms "delta momentum" and "rest mass" oxmorons?"

Niether are. Rest mass is as above. Delta momentum is simply a change in p.

p= m0u/sqrt(1-v2)

Also, E= sqrt(p2 + m02).

" t=dKE right : time is the rate of kinetic enedt.rgy release."

The rate of E change is a dE/dt. t != dE/dt.

141 posted on 10/04/2005 9:54:28 PM PDT by spunkets
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