That is the problem. When researchers tried to repeat the first experiments, they naturally looked for 3.3 MeV neutrons and found none.
So now the theory has to include a mechanism to get cold fusion, without the neutrons but with the energy, since nobody can detect the neutrons.
If you are going to get power from DD, DT, DH, HH, or whatever process, making a mole of fusions is going to result in a mole or two of neutrons that must go somewhere, and they will activate stuff just like the neutrons from fission.
"The neutron produced in reaction 2 has an energy of only 2.45 MeV (similar to the faster fission neutrons), with the He-3 carrying 0.82 MeV. The division of energy in reaction 3 is 1.01 MeV for the triton, and 3.03 MeV for the proton. The two D+D reactions are equally likely and each will occur half the time."
However, the probability of the neutron being captured is dependant on how much material it is passing through, and the neutron capture cross section of that material. So if this is done in "laboratory glassware", some neutrons IMHO are going to get out, as opposed to a massive structure (comparatively speaking) of say a research fission reactor.
If you do get neutron capture (a.k.a. neutron activation), you will likely be getting some radioisotope formation: tritium, isotopes of oxygen, silicon and other elements making up the glassware. Also possibly Nitrogen-16 (occurs when Oxygen-16, the normal isotope, is hit by certain gammas), but n-16 is extremely short lived. N-16 is typically formed in water cooled power reactors, but most of it has beta-decayed to O-16 by the time it reaches the steam turbine. The plant still needs recombiner equipment to deal with the disassociated hydrogen and oxygen (quite exothermic).