I had to ponder this part, though:
"The total angular momentum of the earth moon system, which is spin angular momentum plus the orbital angular momentum, is constant. (The Sun plays apart also) Friction of the oceans caused by the tides is causing the Earth to slow down a tiny bit each year. This is approximately two milliseconds per century causing the moon to recede by about 4 centimeters per year. As the Earth slows down, the Moon must recede to keep the total angular momentum a constant."
Angular momentum relative to what - the Earth, or the Sun? I am having trouble visualizing how the spin of the earth would affect the angular momentum in either case. But when I think about it, he must have meant the angular momentum relative to the Sun (center of mass of the Sun-Earth system).
It seems that the mass of the rotating earth away from the sun has a bigger moment arm than the mass of the earth of closest to the sun, so the faster the earth is spinning, the greater the angular momentum relative to the sun. The "away" mass adds and the "near" mass subtracts, right?
I've never really thought about which way the earth is rotating around the sun, looking from Polaris. It must be CCW, the same way the Earth is rotating on it's axis.
Even though the Sun plays apart in all this, the total angular momentum of the Earth/Moon system must be conserved. Thusly if the Earth slows down it must impart a delta to the orbit angular momentum of the Moon keeping the total system conserved.