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What is the distance between rover wheels (from one side to the other?) That would give some idea of the size of the object, and we could guess the weight (OK, mass) involved here. From the way it looks, to overturn the object (if it is stone) would take considerable force, considering there is little lever arm if the rover ran over it longitudinally.

In earth gravity, a rock 3 ft. long and 4X6 inches would weigh nearly 100 lbs and be pretty difficult to flip with the side of the wheels, unless the substrate is really loose, and the tracks do not support that idea.

"In earth gravity, a rock 3 ft. long and 4X6 inches would weigh nearly 100 lbs and be pretty difficult to flip with the side of the wheels, unless the substrate is really loose, and the tracks do not support that idea."

Perhaps, but I don't think we have enough data to rule it out (what's the gravity there? how heavy is the rover? is the rock solid or hollow? is it a even a rock?). I'm sure the NASA experts will come up with several plausible ideas.

Now, what would have been even more shocking, is if the object had been standing on end with a similar object attached about a quarter of the way from the top and perpendicular to the 1st object so as to form a t (cross). How much fun would that have been to watch the liberal left squirm.

I know, I know. Just wishful thinking, but I do like to see them squirm.

;^D