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To: The_Reader_David
It purports to calculate quantities by summing over all possible embeddings of Riemann surfaces in certain spaces (10 or 11 dimensional), but once one is dealing with higher genus surfaces (imagine more and more handles on your coffee cup) there is no proceedure for 'regularizing' the infinite sum to produce a finite quantity.

Huh?

20 posted on 12/10/2004 8:01:53 AM PST by Dogrobber
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To: Dogrobber
Physicists (since Feynman) have computed things by defining certain infinite sums which (unlike ones you might have met in Calc II) always diverge when interpretted in an ordinary mathematical sense, then finding a way to interpret them differently ('regularize' them) to get finite quantities.

The best one used outside of string theory--in the context of Feynman diagrams, where one's sums depend on all embeddings of graphs (finite bunched of paths that can branch and rejoin)--is to realize that the dimension of the space-time shows up in the sum, turn the dimension into a variable, d, write the sum as a sum ofmultiples of powers of (d-4). It is infinite when d = 4 because you get some negative powers. Just throw away all the terms with negative powers of (d-4) and add up the rest (as in Calc II). Mirable dictu the result agrees with experiment to 14 places after the decimal.

There is no correponding procedure in string theory, where the sums depend on embedding Riemann surfaces (surfaces glued together out of copies disks from the complex plane so that you can tell which complex-valued functions on them have derivatives in the complex sense).

27 posted on 12/10/2004 8:25:35 AM PST by The_Reader_David (And when they behead your own people in the wars which are to come, then you will know what this was)
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