[snarks_when_bored]

Here you go:

(g₈₅ - g₈₇) / g₈₅ = 1.2 x 10^-7

Or:

(g85 - g87) / g85 = 1.2 x 10-7

Or (getting fancier):

(g₈₅ - g₈₇) ÷ g₈₅ = 1.2 x 10^-7

[PatrickHenry]

Nicely done. I see you used double < sub > codes for "on" and another pair for "off," which I'll try to remember next time I need them. Lemme see if it works: H₂O. Yeah. Amazing.