[tanknetter]

Doesn’t 10,000 tons sound a little high for a rock 45 ft. across? I don’t know how to do the math to determine the density for that. Yet they say it wasn’t ‘dense’ like nickel or iron.

10,000 tons is roughly the same as a WWII cruiser, and a bit more than a modern Arleigh Burke-class Destroyer. At 45' across it had to be dense as all hell ...

[COBOL2Java]

At 45' across it had to be dense as all hell ...

Dense enough to be an Obama voter?

[FreedomPoster]

Assume a spherical rock. At r = 22.5’, V = 47,713 ft^cu, or about 1800 cu yds in round numbers.

Concrete density is around 2 tons per yard, so there is 3600 tons. So we’d need some rock significantly more dense that concrete.

By the way, I did the math on 10,000 tons at 40,000 mph, and that comes out to 346,000 tons of TNT worth of kinetic energy.

[SunkenCiv]

The destroyer displaces 10,000 tons of water, which has a lower density than most of the asteroid (Earth’s density is about 4 times that of Jupiter, for example).