The libertarian party measures it’s voters by the thousands doesn’t it?
The R congressman in NH 1 lost by 6000 votes. The libertarian vote in that race was measured in the thousands, 12000 to be exact.
Yes, here is an example from the 1st Congressional District in NH:
Frank Guinta (R - incumbent) 158,659 Carol Shea Porter (D) 171,650 Brandon Kelly (L) 14,251
Had Frank Guinta been able to bring the Libertarian voters into his column he would have won. Probably he could have rounded up some more R voters on election day, since the R GOTV efforts were obviously weaker than the GOTV efforts of the D party. The L party did very little GOTV work. But winning really takes getting more people to choose the R candidate ahead of election day and commit to vote. With no GOTV work to speak of and no chance of winning enough voters chose the Libertarian candidate over the Republican to affect the outcome of the election. A simple formula for victory is for the Republicans to run a candidate who is acceptable to the L voters - many of whom already did choose Guinta over Kelly.
I suggest that getting L voters to vote Republican requires less of a change of position than getting D voters to vote Republican, and can be done while maintaining conservative principles. The L voters mostly want the government to leave them alone, a desire shared with most conservatives.
They'll pick a Republican who shows even limited support for Constitutional government and who will not support intrusive government expansion.