[jonno]

It is a lie mathematically

Wrong. Do the math.

Take 100 voters.

49 support one candidate

51 don't support him

Election day:
49 vote for the candidate
3 of the 51 decide they won't vote with the opposition.

The candidate wins 49 to 48.

How is the above a mathematical lie?

[INVAR]

Yeah, like math so honestly and simply suggested takes place under Cook County Thuggery.

You forgot to add the dead,

the Illegals,

the multiple votes,

the busloads of bussed in homeless,

and whomever else is ‘added’ to the ballot box after the polls close.

You would be surprised how many registered voters there are that outnumber the actual population in any one area controlled by Democrats.

[Psalm 144]

It is simpler than that. As pointed out upthread, if this logical absurdity were true then not voting for Obama is the same as voting for Romney.

Slave thought and slave argument.

Enjoy your servitude and the reward obeisance deserves.

[OldEarlGray]

Who was doing the SWIFT math when Progress for America was being funded by the predators at Ameriquest - and the Republic was being sold up the river?

Best PROGRESSive RATs and RINOs money could buy

We're heading into QE 3 and another round of financial LOOTING  thanks to such manure.

NO SALE

[Sloth]

You suck at math. In the scenario you present, the three voters who do not support the candidate do not have their votes added to his total. If they did, he’d win 52 to 48 instead of 49 to 48. Therefore, the original claim (that a vote withheld from one candidate is a vote for his opponent) is a lie.