Actually, if things stay the way they are right now, it should be 32-0 for Cruz:
"If one candidate wins more than 50% of the National Convention Delegates, that candidate receives all the National Convention Delegates. [Idaho Republican Party State Rules. Idaho Rules for Selection of Delegates to the National Convention and State Convention. Article VI. Section 3.(a)]"
Unless Rubio breaks 20%, looks like Trump will be shut out in Idaho...
Some of you cruzers are as bad as Democrats.
That would explain the snarky Trump supporter stains on this thread.
I think you are wrong about that
(c) If any candidate receives more than fifty percent (50%) of the total vote cast for all
15
candidates in the Republican presidential primary, all delegates available to Idaho under the
16
Rules of the Republican National Committee shall be apportioned to that candidate.
is the language out of the 2016 Idaho Primary
Are you sure you are not looking at the 2012 Caucus manual?
Its 50% of the vote, not delegates
With 65% reporting it’s 14 Cruz. 10 Trump. Rubio is not going to reach 20%. So I guess when the voting is done the other 8 delegates can be awarded. Mississippi 24-13 Trump, 3 to be awarded. Kasich and Rubio were shut out. Michigan
25 Trump, 17 Cruz, 17 Kasich, Rubio 0.
So the total delegate count so far for the night is.
Trump 59
Cruz 44
Kasich 17
Rubio 0
There’s still 8 more outstanding from Idaho and 3 more from Mississippi.Tonight was basically a wash. Right now with 74% reporting Cruz has 43.9%. If he were to get to 50%, he might get all of them and Trump get 0. Can’t figure that one out.