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Why the long-supported quantum electrodynamics theory might need some rethinking
Electronic Products ^
| 12/3/12
| Jeffrey Bausch
Posted on 12/21/2012 11:05:27 AM PST by null and void
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To: null and void
“Exactly equal to the force of the door sill pressing back?”
You forgot opposite. F(12) = -F(21) as in points 1 and 2
21
posted on
12/21/2012 12:04:20 PM PST
by
EEGator
To: GeronL
lol.
Religion is never wrong, it’s just created.
lol
do we have a “Settled Religion” ping list?
22
posted on
12/21/2012 12:04:41 PM PST
by
null and void
(Going Galt: The won't of the people)
To: Mycroft Holmes; layman; null and void; EEGator
Mycroft is almost right.
It's not a trick, not a joke, and not a vector problem.
The formula F = MA is correct.
Irregardless of Mass ... given zero Acceleration the force is zero.
It might be interesting to try the question out on whiz kids you know.
To: GeronL
The scientific method is the best method we have for finding out answers to our questions. You can still believe in God while admitting the scientific method is our best tool.
24
posted on
12/21/2012 12:06:31 PM PST
by
EEGator
To: OldNavyVet
That sounds fishy to me. So if I’m bench pressing and I get stuck half way up, I’m not exerting force? I understand the math aspect, since zero times anything is zero. If my force is zero, what am I exerting?
25
posted on
12/21/2012 12:10:51 PM PST
by
EEGator
To: OldNavyVet; EEGator
Yes. And zero=zero. No ± sign, no sine...
26
posted on
12/21/2012 12:13:10 PM PST
by
null and void
(Going Galt: The won't of the people)
To: OldNavyVet; EEGator
Yes. And zero=zero. No ± sign, no sine, no sighin’...
27
posted on
12/21/2012 12:14:00 PM PST
by
null and void
(Going Galt: The won't of the people)
To: EEGator
Effort. But you are accomplishing no work...
28
posted on
12/21/2012 12:16:53 PM PST
by
null and void
(Going Galt: The won't of the people)
To: null and void
The ion is actually very different from a helium atom. In the latter case, the atom is charge-neutral and all coulomb fields fall off much faster than r^-2. The ion, meanwhile, has a 20e positive charge which can induce charges in the surroundng walls of the equipment and thence modify the electron orbits.
It is possible that they have tried to compensate for this, but the compensation calculation could be a very difficult one to do accurately.
29
posted on
12/21/2012 12:21:07 PM PST
by
expat2
To: null and void
However, if no errors are found in the theory and the NIST experiment is correct, some physics outside of QED must be present.
***Physicists have been resisting this notion for 23 years, trying their best to deny the data coming from other Condensed Matter Nuclear Science Experiments known as Cold Fusion.
30
posted on
12/21/2012 12:22:28 PM PST
by
Kevmo
("A person's a person, no matter how small" ~Horton Hears a Who)
To: EEGator
If my force is zero, what am I exerting? Pressure.
To: EEGator
“Im not exerting force?”
You are exerting force. But it has become equal to the force of gravity.
32
posted on
12/21/2012 12:32:22 PM PST
by
toast
To: OldNavyVet
ΣF=0
ΣM=0
(assuming static equilibrium)
33
posted on
12/21/2012 12:35:07 PM PST
by
Rodamala
To: OldNavyVet
Reminds me of a physics professor that opened the semester leaning heavily on a door sill and asking students to estimate the force of his pressing action? Do you really mean sill? The sill is a raised segment at the floor. Or did you mean the door jamb (the vertical member of a door frame. The top horizontal member of the door frame is called the head. So was the prof leaning drunk or fall down on the floor drunk?
34
posted on
12/21/2012 12:42:51 PM PST
by
Covenantor
("Men are ruled...by liars who refuse them news, and by fools who cannot govern." Chesterton)
To: OldNavyVet
That’s not true. There’s still a force that you are exerting on the doorframe, it’s just not strong enough to overcome any counteracting forces, to create an acceleration in the doorframe. You’re still exerting a force though.
To: EEGator
That sounds fishy to me. So if Im bench pressing and I get stuck half way up, Im not exerting force? I understand the math aspect, since zero times anything is zero. If my force is zero, what am I exerting? You have to take gravity into account. You are exerting upward force, which is exactly balanced by the downward force coming from gravity.
36
posted on
12/21/2012 1:38:13 PM PST
by
PapaBear3625
(You don't notice it's a police state until the police come for you.)
To: null and void
Effort. But you are accomplishing no work... Tell that to the ATPase in the Actin-Myosine filaments
To: All
Thanks for all the feedback.
38
posted on
12/21/2012 4:06:36 PM PST
by
EEGator
To: skinkinthegrass; Ernest_at_the_Beach; 6SJ7; AdmSmith; AFPhys; Arkinsaw; allmost; aristotleman; ...
39
posted on
12/21/2012 7:53:53 PM PST
by
SunkenCiv
(https://secure.freerepublic.com/donate/)
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