Posted on 07/29/2005 6:03:12 AM PDT by OESY
LOL. Bank? Willie doesn't trust banks. He keeps all his spare change in a large mason jar buried under his front porch. That way it's safe from all the transnational corporations.
Exactly, but according to the chart the Earth took more than an an extra second to complete the year in 1900. So either the Earth is turning more quickly since then or it's going around the sun more slowly.
Therefore, the Earths rotates about 360.9856465 degrees per day of UT, with respect to distant stars and pretty close to 360 degrees per day (one average) with respect to the nearest star, the Sun. One day of UT equals 86,400 seconds of UT.
Universal Time (UT) is conventionally defined by an agreed to rotational rate of the Earth, measured against the distant stars. When the Earth rotates a given number of degrees, exactly so many seconds or days of UT time has elapsed. If you do all the math right (and I havent given you enough information here to do it) it turns out there are 86,164.09074 seconds of UT in a sidereal day, the time it takes the Earth to rotate once on its axis with respect to the fixed stars. Its approximately equal to 86,400 times (365.2522/[365.2522+1]).
Imagine that you are an astronomer, and measure the transit of a certain bright star, say Sirius, across the cross hairs in a telescope pointed due south, at the correct elevation to catch it. (You happen to be in the Northern Hemisphere.) At exactly that moment you start a timer that counts atomic seconds. The next evening you snap a photograph of the timer just as Sirius transits again. (Fast aperture!) In the interim you know that precisely 86164.09074 seconds of universal time has elapsed, by definition. The timer may read something else, the difference is the difference between atomic time and UT. You're persistent, and besides you have a NSF grant, so you keep this up for 365 days, at which time precisely 31536057.211 seconds of UT will have passed. (The star transits a littler earlier every day because a sidereal day is shorter than solar day, in 365 days you observe 366 transits.)
You compare your timer to the expected 31536057.211 seconds. If it's less you say the Earth is running fast, if it's more you say the Earth is running slow. The claim is that if you had performed this experiment sometime around 1900, the timer would have indicated over a second more than a expected, in 1500 as second less.
You know, when C'thulhu awakes from slumber in R'lyeh and takes over the world, none of this crap is gonna matter.
;-) :-D
Um, it's more like 365.2422 (.2422 * 4 just about equalling the leap year day - less the slowing-down and occasional added seconds).
Yep. Which means that watch and clock company stocks will go through the roof. Everyone will have to get a new watch and a new set of clocks.
I think I will make a long term investment in Seiko and Citizen.
NO! No, with respect to the distant stars it's more like 366.2422. The motion of the Earth around the Sun induces an apparent west to east motion of the Sun. If the Earth did not rotate with repect to the fixed stars, every year the Sun would rise once in the west and set once in the east, with six months of night and six months of daylight, everywhere. Stars (other than the very nearest one, the Sun) 'transit the meridian' about four minutes earlier every day. In 365 calendar days, most stars will transit 366 times. Ptolemy knew this, the ancient Chaldeans knew this, (without as much precision as we do today) no later than early in the first milleum BC.
The transits of the distant stars are much, much more regular than the transits of the Sun. As you know, the Sun only transits once every 24 hours on 'average', where average is over a solar year. The timing of Solar transits, which unlike risings and settings are the same regardless of laditude, vary plus or minus about 15 minutes over the course of a year, due to the obliquity of the ecliptic ('tilt of the Earth') and ecentricity of the Earth's orbit. The difference between mean solar time (as in "Greenwich Mean Time") and apparent solar time is given by "the equation of time". The ancient Chaldeans had a pretty good handle on the equation of time.
The difference between the two is not great, less than 25 parts in a billion or about one second every 500 days and is expected to change by only about that amount every century for the forseeable future. This is far better than the accuracy of even the best quartz timepiece. There would have to be some new time distribution services, something like WWV-UT to distribute new time codes.
I suggest that most computers running NTP would be completely compatible with such a system, while NTP does not handle leapsecond well at all.
Yah, okay, you're right - I was thinking solar days; not sidereal days.
(Hate to pile on but) the mean "solar year" is approximately 365.24219 twenty-four hour days. The Gregorian calendar approximates this as 365 +1/4 -1/100 + 1/400 = 365.2425. The Gregorian Calendar gains a day every 3200 years or so, the Julian calendar gained about three days every 400 years. The reason that the sidereal day does not equal 24 x 365.24219/(365.24219 +1) hours is because of the difference between the sidereal year and the solar year. It takes the earth about 365.256363 days to return to the same point in its orbit with respect to the fixed stars. The difference between this and the solar year is due to the precession of the equinox. We like our years to reflect the seasons, not the positions of the sun. If we used a sidereal calendar the seasons would drift about a two days every three centuries.
I didn't mean to quibble, but the Earth's rotation is measured with respect to fixed stars, actually distant pulsars billions of light years away. Universal time is actually defined in terms of sidereal time.
It's an important distinction because things like tides and equipotential surface (shape of the earth) are determined by motion with respect to an inertial (sidereal) reference frame.
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