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Math question?

Posted on 05/07/2015 7:27:31 AM PDT by MNDude

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1 posted on 05/07/2015 7:27:31 AM PDT by MNDude
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To: MNDude

1 in 6. Odds do not change based on number of times. The odds are the same for every roll of the dice.


2 posted on 05/07/2015 7:29:23 AM PDT by Louis Foxwell (This is a wake up call. Join the Sultan Knish ping list.)
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To: MNDude

Well for the dice, its exactly the same, prior rolls do not influence latter rolls.


3 posted on 05/07/2015 7:29:48 AM PDT by American in Israel (A wise man's heart directs him to the right, but the foolish mans heart directs him toward the left.)
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To: MNDude

multiplication. potentially factorials.


4 posted on 05/07/2015 7:30:39 AM PDT by Paladin2
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To: MNDude

80% chance, I believe.


5 posted on 05/07/2015 7:30:43 AM PDT by gorush (History repeats itself because human nature is static)
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To: Louis Foxwell

Exactly.


6 posted on 05/07/2015 7:30:54 AM PDT by Gamecock (Why do bad things happen to good people? That only happened once, and He volunteered. R.C. Sproul)
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To: MNDude

I’m no math whiz either, but I think in the case of dice it would be expressed in a percentage as 100/6 = 16.6667%


7 posted on 05/07/2015 7:32:31 AM PDT by Fester Chugabrew (Even the compassion of the wicked is cruel.)
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To: MNDude

How about:

(number of times you roll the dice) * (1/6)

of course, this proves statistians are liars, in that you could theoretically roll it 6 times and never get the number you were looking for.

(There’s actually a real way to do this, but I don’t have any coffee in me.)


8 posted on 05/07/2015 7:33:07 AM PDT by Jewbacca (The residents of Iroquois territory may not determine whether Jews may live in Jerusalem)
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To: MNDude

What’s the event?

Is it a human influenced event?


9 posted on 05/07/2015 7:33:52 AM PDT by IMR 4350
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To: MNDude
What are the chances I will get a "five" if I roll the dice six times?

Your wording is a little unclear. If you mean "What are the chances that I will get a 'five' six times in a row?", that that would be one thirty-sixth.

Regards,

10 posted on 05/07/2015 7:35:11 AM PDT by alexander_busek (Extraordinary claims require extraordinary evidence.)
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To: gorush

(83%, actually)


11 posted on 05/07/2015 7:35:26 AM PDT by gorush (History repeats itself because human nature is static)
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To: Jewbacca


Sorry, the real way to do this is to note you have a 5/6 chance of not hitting your number each roll.
12 posted on 05/07/2015 7:36:59 AM PDT by Jewbacca (The residents of Iroquois territory may not determine whether Jews may live in Jerusalem)
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To: Louis Foxwell
Interesting factoid. My brother was once at a crap table and observed 5 hard 10's rolled in a row.

That 'can't' happen....but it did.

13 posted on 05/07/2015 7:37:35 AM PDT by JPG (Lefty reporters doing battle with Sen. Cruz will continue to be chewed-up and spit-out.)
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To: MNDude

Just calculate the chance of NOT getting a 5 in 6 roles of the dice:

5/6 * 5/6 * 5/6 * 5/6 * 5/6 * 5/6 = 0.335

So the chance of getting at least one 5 is 1 - 0.335 = .665

or 66.5%


14 posted on 05/07/2015 7:37:40 AM PDT by pelican001
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To: alexander_busek

OK, basically I’m trying to put together a call center to reach out to our clients. I know that there’s a 16% chance someone will connect with someone while making a phone call.

So I’m trying to calculate how many people we will reach if we make calls out to 1000 people, and we call each one up to six times. (stop calling those once we’ve made contact of course).


15 posted on 05/07/2015 7:40:35 AM PDT by MNDude
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To: pelican001

Just calculate the chance of NOT getting a 5 in 6 roles of the dice:

5/6 * 5/6 * 5/6 * 5/6 * 5/6 * 5/6 = 0.335

So the chance of getting at least one 5 is 1 - 0.335 = .665

or 66.5%


This is the correct answer.


16 posted on 05/07/2015 7:41:03 AM PDT by So Cal Rocket (Task 1: Accomplished, Task 2: Hold them Accountable!)
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To: MNDude
What are the chances I will get a "five" if I roll the dice six times?

Think of it this way. What's the chance of rolling one die one time and NOT getting a 5? It's 5/6.

So the chances of rolling a die six times and not getting a 5 is: (5/6) to the power of 6. That's 0.335. Then subtract that from 1 (100%). Result: 0.665 or 66.5%.

Disclaimer: I did this on a untrustworthy calculator. Please do not use my result to build a rocket or anything like that.

17 posted on 05/07/2015 7:42:08 AM PDT by Leaning Right (Why am I holding this lantern? I am looking for the next Reagan.)
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To: Jewbacca

Like this for the 36 rolls:

The “36” is in superscript (ie to the 36th power)

1-(5/6)36 = 99.86%


18 posted on 05/07/2015 7:42:38 AM PDT by Jewbacca (The residents of Iroquois territory may not determine whether Jews may live in Jerusalem)
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To: pelican001
Just calculate the chance of NOT getting a 5 in 6 roles of the dice:

5/6 * 5/6 * 5/6 * 5/6 * 5/6 * 5/6 = 0.335

So the chance of getting at least one 5 is 1 - 0.335 = .665

or 66.5%

Excellent!

19 posted on 05/07/2015 7:43:13 AM PDT by bkepley
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To: MNDude

1- (.84) 1000 = answer

The 1000 is in superscript.


20 posted on 05/07/2015 7:43:50 AM PDT by Jewbacca (The residents of Iroquois territory may not determine whether Jews may live in Jerusalem)
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