Sorry, the real way to do this is to note you have a 5/6 chance of not hitting your number each roll.
How about:
(number of times you roll the dice) * (1/6)
of course, this proves statistians are liars, in that you could theoretically roll it 6 times and never get the number you were looking for.
(There’s actually a real way to do this, but I don’t have any coffee in me.)
Wrong. You apparently missed the posts that state very clearly for dice rolls the answer is independent of previous results. This is not a closed box with balls that are drawn and reducing the opportunity case ( at least not as described by the poster)