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To: Olog-hai
> Reporters don’t typically get that the kilogram unit of measure is one of mass and not of weight ...

They also manage to conflate speed (a scalar) and velocity (a vector), energy and power, and on and on....

I wish the scientists all the best luck in their quest for the unchanging kilo. An esoteric problem if ever there was one.

2 posted on 03/28/2015 1:33:06 AM PDT by dayglored (Listen, strange women lying in ponds distributing swords is...sounding pretty good about now.)
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To: dayglored

“A pint’s a pound, the world around.” There, problem solved.


10 posted on 03/28/2015 2:38:43 AM PDT by steve8714 (Traditional Catholics want Latin Mass. Traditional Muslims want your head.)
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To: dayglored

I hope that the NEW kilogram will drop the sexism, racism, and bigotry of the current kilogram which is a product of dead white European males. It is way beyond time to fundamentally transform the kilogram.


12 posted on 03/28/2015 3:00:06 AM PDT by Flash Bazbeaux
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To: dayglored

Thus and such many atoms of thus and such an isotope — one of the easiest things in principle if not in practice. There has to be more to the story than this.


16 posted on 03/28/2015 3:33:53 AM PDT by HiTech RedNeck (Embrace the Lion of Judah and He will roar for you and teach you to roar too. See my page.)
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To: dayglored

The weight of a particular mass involves a number of “forces”. The first would be gravity, probably the most constant however even that could fluctuate due to the moving mantel beneath the earth’s crust as well as altitude of the mass.

The other forces acting on the mass are centrifugal force, which makes a mass weigh less (buy a surprising amount) at the equator than at the north or south pole. Even that can’t adjusted for latitude accurately because of wobble as well as altitude. Speaking of altitude, “sea level” itself is different from the equator to the upper and lower latitudes.

buoyancy is not really a force but it effects the weight as well and of course it continually changes with air pressure.

SO... The way to solve the problem at hand would be to take gravity out of the equation and substitute an electrostatic force field.

Define a kilogram as the potential necessary to produce a kilogram of force on the plates of a parallel plate capacitor of some dimension in a hard vacuum. The dielectric properties of a vacuum would be constant, even removing temperature from the equation. If the plates were vertical, gravity and centrifugal force would be removed as well.


41 posted on 03/28/2015 6:47:34 AM PDT by babygene
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