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The lag is a little over a second.

So then, for the purposes of naked-eye astronomy, the moon is where it appears to be, or nearly so -- according to you. But the difference between the Sun's observed position and its actual position is an enormous 2.1 degrees -- again, according to you.

If you are on a planet that is revolving at 16.6 minutes per revolution and a sniper with a laser is one Au from you...

Let us stop the sniper's shot by interposing the moon. We have now learned where the moon must be -- in the LeGrandeic System -- to cause a total solar eclipse. The moon must occlude the actual sun. But while the moon is where it appears to be in the sky or nearly so, the observed sun -- the corona and photosphere -- is off by 180 degrees. Therefore during a solar eclipse on this planet, the eclipse is observed to be 180 degrees away from the observed moon -- according to you.

Let us return to the Earth. The moon is where it appears to be, but the observed Sun is 2.1 degrees away from its actual position, according to you. Therefore during a total solar eclipse, the moon must be 2.1 degrees away from the observed eclipse. But the painful astronomical fact (which I feel you will probably not face gracefully) is that this is false, as any grade-schooler knows.

There's not much use in more rambling about water-trucks, driving in the rain, skeet-shooting, or laser-sniping. As if any such arguments, no matter how convoluted or contrived, are going to make someone who isn't a lunatic believe that the moon is 2.1 degrees away from the observed Sun during a solar eclipse.

Let us return to the Earth. The moon is where it appears to be, but the observed Sun is 2.1 degrees away from its actual position, according to you. Therefore during a total solar eclipse, the moon must be 2.1 degrees away from the observed eclipse. But the painful astronomical fact (which I feel you will probably not face gracefully) is that this is false, as any grade-schooler knows.

You keep trying to turn this back into a three body model. The Sun is only 2.1 degrees behind strictly in relationship to an observer on the earth, in a two body model. In the two body model there is essentially no difference between two stationary objects with one of the them spinning or having one of them orbit the other object. Adding a third body invalidates the two body model.

Remember this is all based on mrjesses merry go round model. I would like you to explain to me how to determine in a two body model how you can definitively determine which body is orbiting or which body is spinning? I think this is where you are confused.