Thanks for the post and good luck with your target practice.
And you have I’ve given me one more opportunity to apologize for my massive screwup:
A 58 foot drop in 3 seconds was incorrect. The formula is correct but the calculation went awry.
The real 3 second drop: 144 feet.
Rule of thumb for those in the field without a ballistic computer/calculator/slide rule: NOT 3 x 32 fps, squared- that 32 fps drop is not a constant, and only applies to the terminal velocity after the first second- the initial rate of fall having been zero.
[The speed rises as the square root of height, but in direct proportion to time.]
The speed after 3 seconds is 96 feet per second. The total distance is 144 feet. Speed is acceleration times time. Distance is average speed times time. With constant acceleration, the average speed is the final speed divided by two.
So for the three-second bullet flight, the drop of the projectile [unless it's a spheroid musket or cannon ball, in which case see Robins or Bouriee] will approximate the height of a 14-story building- which sounds about right, compared to this shorter range and shorter church-steeple height elevation.