Otherwise, the 40 delegates are split evenly between all those who get at least 15% of the vote.
So if both Trump and Cruz finish between 15-49%, they will both come away with 20 delegates. Even if Cruz is at 49% and Trump is at 15%.
If Kasich also gets at least 15%, then the 40 delegates are split three ways with Cruz, Trump and Kasich all getting 13 each. I suppose the delegate left over would go to whoever finished highest.
Let me know if I'm wrong but that's the way I understand it.
If I understand correctly, than this could be a pretty decent night for Trump if he gets the 58 delegates in AZ and then picks up maybe 13 in UT. Not to mention the 9 available in American Samoa.
I believe that they are split proportionally, not evenly.
Trump was at 11% in the poll I saw which means he wouldn’t get any delegates in Utah. Romney will make sure all delegates in Utah are his people anyways. Trump should have fought for this at least to get 15%. Every bit counts
I believe you are right, except that the delegates will be divided proportionately, not evenly. So, if the WTA trigger of 50% is not met by any candidate, then any candidates that exceed the 15% threshold will divide the delegates proportionately.
Exception: If two or fewer candidates meet the 15% threshold and the 50% trigger is not met, the threshold I’d dropped, and the division is truly proportional. With only three in the race, that is certain if none gets the 50%
Example: If Trump gets 14%, Kasich gets 38% and Cruz gets 48%, then the delegates would be T 6, K 15, C 19.
Example: If Trump gets 20%, Kasich gets 32% and Cruz gets 48%, then
the delegates would be T 8, K 13, C 19.