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To: Teacher317
Among those self-identifying as TEA Party voters (18 percent of those polled) it was: Cruz 35, Walker 16, nobody else over 8

Among those GOP voters who do NOT self-identify as TEA Party voters (24 percent), it was: Perry 17, Cruz 14, Bush 11, Rubio 8, nobody else over 6.

20 posted on 06/22/2015 10:11:21 AM PDT by Teacher317 (We have now sunk to a depth at which restatement of the obvious is the first duty of intelligent men)
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To: Teacher317
Hmmm... here's the important math... 34 percent self-identified as Democrats (and I assume we can set their number of Cruz votes at zero)... so...

76 percent identified as GOP/TEA or Dem... so 24 percent did not choose a party... the "independents" that basically decide every election.

If Cruz got 20 percent overall (0.20), and it was 35 percent of 18 percent TEA (0.063) plus 14 percent of 24 percent GOP (0.0336), and zero percent of 34 percent DEM (0.0)... that means that he is getting FORTY THREE percent of the Independents (.43 x .24 = the remaining 0.103)

Please triple-check my math and humiliate me if I am wrong here.

21 posted on 06/22/2015 10:33:36 AM PDT by Teacher317 (We have now sunk to a depth at which restatement of the obvious is the first duty of intelligent men)
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