To: Lurkina.n.Learnin
Assuming they are saying the odds on game 6&7 are the same, the Dodgers would have to have a 61.6% chance to win each game to have a 38% chance to win both.
24 posted on
10/29/2017 11:23:06 PM PDT by
KarlInOhio
(The Whig Party died when it fled the great fight of its century. Ditto for the Republicans now.)
To: KarlInOhio
"Assuming they are saying the odds on game 6&7 are the same, the Dodgers would have to have a 61.6% chance to win each game to have a 38% chance to win both." Exactly right.
51 posted on
10/30/2017 12:14:13 AM PDT by
Neanderthal
(When you import the third world you become the third world)
To: KarlInOhio
No. They are saying that a team who wins Game 5 and is traveling to the other teams field for Game 6 has a 62% chance of winning the series. If that team loses game 6 then the odds change to against them.
57 posted on
10/30/2017 1:22:41 AM PDT by
Az Joe
(Gloria in excelsis Deo)
FreeRepublic.com is powered by software copyright 2000-2008 John Robinson