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To: Steelfish
"Forty percent (40%) of likely voters in the Buckeye State have already voted. Obama leads 60% to 37% among these voters."

That can't be good...

2 posted on 11/05/2012 10:39:06 PM PST by Wayne07
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To: MrShoop

That’s scary!


5 posted on 11/05/2012 10:43:13 PM PST by Steelfish (ui)
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To: MrShoop

Or accurate. I believe that the actual early vote percentage in Ohio is more like mid 20’s percentile


6 posted on 11/05/2012 10:43:34 PM PST by johncocktoasten (Practicing asymetrical thread warfare against anti-Palin Trolls)
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To: MrShoop

It’s not 40%. The Secretary of State website shows that 1.6MM voters have voted. Based on 2008 turnout that’s about 28%.


7 posted on 11/05/2012 10:44:03 PM PST by hawaiian
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To: MrShoop

Obama’s early vote totals are way down in Ohio from 2008. Mitt is fine being Republicans outnumber Democrats in the state. Plus, he will carry independents.


9 posted on 11/05/2012 10:45:12 PM PST by xuberalles ("The Right Stuff" Conservative Novelties http://www.zazzle.com/xuberalles)
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To: MrShoop

Based on those number Romney needs 59% of the remaining voters to win OH EVs

Its all down now to GOTV in FL, OH, WI, PA, VA.

Romney has a very good shot at being the next President provided these states Vote.


11 posted on 11/05/2012 10:48:06 PM PST by Bailee
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To: MrShoop

How do they know what is inside of the votes. Is it by exit polling or do they assume democrat votes turned in will be votes for Obama. Do you think every democrat will vote for Obama?


14 posted on 11/05/2012 10:48:53 PM PST by funfan
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To: MrShoop
Ninety-three percent (93%) have made up their minds whom they will vote for, and it’s Obama 50%, Romney 49% in this group.

Forty percent (40%) of likely voters in the Buckeye State have already voted. Obama leads 60% to 37% among these voters.

Projected 50% for Obama and votes counted equals 60%?
Projected 49% for Romney and votes counted equals 37%?

Does this mean the ACTUAL didn't match the projected? So, a voter fraud swing for 0bama of 10%? Am I reading this wrong?

22 posted on 11/05/2012 10:57:42 PM PST by Obama_Is_Sabotaging_America
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To: MrShoop
Forty percent (40%) of likely voters in the Buckeye State have already voted. Obama leads 60% to 37% among these voters.

There's something wrong with those numbers. If that was indeed the case, that would be the headline in the Rasmussen article. And more would be made of it in the article. But it isn't.

23 posted on 11/05/2012 10:57:52 PM PST by norcal joe
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To: MrShoop

Newt is the only one who has pointed out that democrats voting early does not mean they’re voting for obama. I doubt very seriously if they’re voting 100% for the Kenyan. But I am sure 100% of the republicans are voting for Romney.


24 posted on 11/05/2012 10:58:10 PM PST by Terry Mross (To former friends and relatives. Don't ever contact me if you still support obama.)
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To: MrShoop

STRONGLY disputed, both in actual numbers and percentages as per Jay Cost on Twitter. Wasserman (a lib) admitted to Nat Silver ha their turnout model is wrong based on Red county turnout.


75 posted on 11/06/2012 4:09:23 AM PST by LS
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