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How much reserve needed in power supply diodes? Sunday Night Electronics...
Me | 2/3/2024 | Paul R.

Posted on 02/03/2024 5:48:43 PM PST by Paul R.

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The asterisks:

*Strictly speaking, this heater already has a half power setting, but it achieves it by turning off one of the two elements, letting the other run full blast. This results in:

1) A likely shorter element life -- bummer, as this heater is ceiling mounted, facing down, and a pain to take down if need be. Plus, elements are sometimes hard to find and disassembly is "significant".

Best yet, this setup makes it possible for me to run at 1/4 power - great in cool but not cold conditions, and easier on the thermostat contacts for sure.

2) The switch to change power is literally a pull switch -- who knows how long that thing is going to last.

3) Illumination via the elements is NOT particularly desired -- operating both elements at half power is rather than one at full power is less obtrusive.***

**I may add a SMALL 600v capacitor to kill any RF that might be generated.

***I've built a small version of this before: In that case I'm operating a 750 watt 230/240 v quartz heater off 120v, and then doing the rectification bit for the "low" setting. That one heats a chicken house and is so much better than brooder lamps, it isn't funny! The visible light emitted is nil, basically infrared only, so the chickens sleep. Plus, the element will probably outlive me. :-)

1 posted on 02/03/2024 5:48:43 PM PST by Paul R.
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To: Paul R.

Your beat estimate of potential demand plus 50%.


2 posted on 02/03/2024 5:54:34 PM PST by Repeal The 17th (Get out of the matrix and get a real life.)
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To: Paul R.
Maybe I should have called this "DIY Sunday Night Electronics." ;-) Forgot to mention that the series diode for half power is used in some home use quartz and resistive wire heaters.

I've also modified to switched series vs. (original) parallel element wiring to run elements "easy" but that takes a bit more of a switch, and I've definitely never seen a pull switch like that...

3 posted on 02/03/2024 5:55:34 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: Repeal The 17th

PFFFTT.......!!!


4 posted on 02/03/2024 5:56:09 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: Paul R.

If you have a few in your parts box, then build it, run it and see if it blows up. It probably wont, but hey, this is the excitement of tinkering of electronics.


5 posted on 02/03/2024 5:59:16 PM PST by RFEngineer
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To: Repeal The 17th

It’s a custom job for me. Tho’ I suppose it MIGHT be marketable to have a 4 heat setting heater? In any event, such diode control is used in some (maybe 20% of the market?)
floor standing space heaters.


6 posted on 02/03/2024 5:59:19 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: Repeal The 17th

Amen to that


7 posted on 02/03/2024 6:01:01 PM PST by al baby (I know sarcasm )
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To: RFEngineer

Well, yeah, but I’m really curious how diode “overhead” is generally “figured” / estimated. The empirical data should go back to the origins of the p/n junction, I’m sure!


8 posted on 02/03/2024 6:02:14 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: RFEngineer

When i found out you could pop capacitors plugged into a switched outlet boy we had fun


9 posted on 02/03/2024 6:02:51 PM PST by al baby (I know sarcasm )
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To: Paul R.

Temperature coefficient of nichrome wire is pretty low - not a problem for current changes here. The 6.5 amp theoretical would go to 7 amps - maybe.
Parallel a couple of rectifiers. Put a .2 or .5 ohm resistor in series with each to keep the current division reasonably equal. Watch the wattage on the resistors.


10 posted on 02/03/2024 6:03:51 PM PST by dagunk
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To: RFEngineer

I suppose I could start with 2 diodes in parallel, if it runs cool, take one out for the next project. :-)


11 posted on 02/03/2024 6:04:40 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: Paul R.

Isn’t the element/elements accessible by removing a back plate and allowing access to remove them?


12 posted on 02/03/2024 6:04:50 PM PST by mythenjoseph (Islam has NO place in a Christian society.)
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To: al baby

We charged capacitors up to 350V and then played hot potato.


13 posted on 02/03/2024 6:08:23 PM PST by fretzer
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To: dagunk

That (current coefficient) lines up with what I observed in my smaller project, granted that I was starting off at half voltage to begin with, so I never got close to the element being “bright”.

Noted on the resistors - good point.


14 posted on 02/03/2024 6:08:26 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: al baby

Oh, heck, hook up a woofer with, say, cone damage, and with maybe a 2” voice coil to 60 Hz 120 VAC!


15 posted on 02/03/2024 6:10:56 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: Paul R.

done that also


16 posted on 02/03/2024 6:12:58 PM PST by al baby (I know sarcasm )
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To: mythenjoseph

No, one has to go in from the front; some significant disassembly involved. Consumer unit — I don’t think the mfgr. really intended repairs...

But, that said, the ceiling mount is the 1st deterrent, and I’m not getting younger.


17 posted on 02/03/2024 6:14:02 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: dagunk; Paul R.
> Parallel a couple of rectifiers. Put a .2 or .5 ohm resistor in series with each to keep the current division reasonably equal. Watch the wattage on the resistors.

Roger that. Any two diodes, even from the same manufacturing batch, will have somewhat different forward voltages for a given current. So while they will tend to share the current, it won't be 50/50.

Placing a very low resistance in series with each diode means there will be a small V=I*R voltage drop across the resistors, which added to the forward voltage of each diode, will tend to equalize the current in each parallel leg.

You can do that with two, three, or more diodes if needed.

I use as a rule of thumb to drop 0.2V across the resistor (assuming silicon diodes with 0.6 to 0.7 forward voltage). And definitely watch the wattage, it can be surprising at high currents.

YMMV.

18 posted on 02/03/2024 6:16:17 PM PST by dayglored (Strange Women Lying In Ponds Distributing Swords! Arthur Pendragon in 2024)
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To: al baby

;-)


19 posted on 02/03/2024 6:17:32 PM PST by Paul R. (Bin Laden wanted Obama killed so the incompetent VP, Biden, would become President!)
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To: Paul R.

Silicone makes lousy semiconductors. Pretty good to seal gutters. Look to Mr. Schottky.


20 posted on 02/03/2024 6:19:08 PM PST by sasquatch (Do NOT forget Ashli Babbit! c/o piytar)
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