[WhiskeyX]

You neglected the time dilation effects as the approach to the event horizon begins to freeze the external perception even as the internal perception seems to be normal. Don’t forget the broadeening of the physical space from the external view which will ultimately smear the dimension across the horizon even as the longitudinal axis is being stretched.

[FroggyTheGremlim]

WhiskeyX - are you a relativity physicist?

[dr_lew]

The extreme tidal effects are not specifically associated with the event horizon. The equation I derived was a classical rule of thumb for the tidal stretching on a scale of "d" in terms of "g" at a distance "r" from an object of 1 Earth Mass:

a = g R²d / r³ , using R for the radius of earth

This is the "tidal force" between two objects at distance d along a radius from the central mass. For a = g we require r = (R²d)^1/3 or

r = (d/R)^1/3 R

Suppose we deem a tidal force field of 1 g/cm to be utterly disruptive of the human body, which it seems it surely would be. Then

(d/R)^1/3 R = ( 6.4e8 )^-1/3 R = R/861 = 7.4 km

But the Schwarzschild radius of earth is about 1 cm, so there could be no question of any kind of familiar object even approaching the event horizon there.