Free Republic
Browse · Search
General/Chat
Topics · Post Article

To: dr_lew

One honcho at todays press briefing mentioned that the retractor reels activated even though the harpoon darts didn’t fire. Maybe he was trying to clarify what you heard him say yesterday? Keep in mind that they theorize that a comet is made of ice, so I am sure the harpoon anchors were designed to embed in ice. Suppose a comet is rock. I think that if you tried to fire ice-harpoons into solid rock you might just knock yourself a half-mile or so away from the comet. Should we be buying this half-mile high bounce explanation (from a meter per second speed on impact of an object weighing a gram)?


38 posted on 11/13/2014 7:00:33 PM PST by HandyDandy (Don't make-up stuff. It just wastes everybody's time.)
[ Post Reply | Private Reply | To 22 | View Replies ]


To: HandyDandy
(from a meter per second speed on impact of an object weighing a gram)?

The mass of the lander is given as 100 kg. At 10-4 g that is 10 gram-mass units of "weight" on earth. In a constant g-field of this strength, the height of a 1 m/sec launch is 1/2 g t2 = 1/2 v2 / g = 500 meters . It should have rebounded less than this, as the landing was "damped", but I think the 1 km value was supposed to be a lateral distance, so it's of the right order.

39 posted on 11/13/2014 7:20:42 PM PST by dr_lew
[ Post Reply | Private Reply | To 38 | View Replies ]

Free Republic
Browse · Search
General/Chat
Topics · Post Article


FreeRepublic, LLC, PO BOX 9771, FRESNO, CA 93794
FreeRepublic.com is powered by software copyright 2000-2008 John Robinson