[justlurking]

Let's see...for a 40 ft turning radius:
(20 m/hr)*(5280 ft/sec)*(1 hr/3600 sec) = 30 ft/sec
a = v*v/r = (30 ft/sec)*(30 ft/sec)/(40 ft) = 23 ft/sec^2,
or about .7 g.

Thank you, I really appreciate it. Working backwards, that means that a 10 mph turn is about .35g. That gives the laypeople an idea of how much force we are really talking about.

[Palmetto]

No, half the speed would be 1/4 the accel, or .175 g.

[thesharkboy]

Working backwards, that means that a 10 mph turn is about .35g.

Actually, the acceleration varies as the square of the speed, so a 10 mi/hr turn with a 40 ft radius would be around 0.17 g.