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To: MacDorcha
Think of performing arithmetic, but when you give the final answer, give the remainder upon division by 8.

1*1=1

3*3=1

5*5=1

7*7=1

Furthermore, if you multiply any two of {1,3,5,7}, you get something in that set. But with this kind of arithmetic, 1 has four square roots.

55 posted on 03/25/2005 9:17:50 AM PST by AmishDude (The Clown Prince-in-a-can of Free Republic!)
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To: AmishDude

But this (from the article) math is based in addition and groupings.

Though what you were going over intrigues me. But I don;t think I'm talking out of place in saying it does not dispute my assertion towards the article.


74 posted on 03/25/2005 9:34:01 AM PST by MacDorcha ("Do you want the e-mail copy or the fax?" "Just the fax, ma'am.")
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