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To: new cruelty
After that he never purchased another ticket, noting that it really didn't make any sense since the chances of him winning again were even lower than before.

Well, actually, his odds of winning again are not in any way affected by his previous winnings. Each drawing is an independent event with its own odds. Just like spins on a roullette wheel.
60 posted on 01/08/2004 10:33:26 AM PST by 303george

To: 303george
...his odds of winning again are not in any way affected by his previous winnings.

Sigh. Yes, I agree. But thank you. Some people need it spelled out for them.

74 posted on 01/08/2004 10:41:05 AM PST by new cruelty ("But there are also unknown unknowns — the ones we don't know we don't know." You know?)

To: 303george
Just like spins on a roullette wheel.

Just a thought... humor me.

Regarding roullette, there is a strategy I am interested in trying out. There are many tables that display the results last several spins- such as the number of times the ball has landed on red, black, or green; odd or even numbers; first 12, second 12, third 12, zero, or double zero; first column, second column, or third column; and so on.

Based on these results, for example, if the ball has landed on red 5 out of the last 6 spins, the odds are the next number it lands on will be black. The odds of the ball landing on green exist, but it seems the odds for black are greater.

Anyway. Using the above example, the player bets \$10 on black. The ball lands on red. The player loses. Now the ball has landed on red 6 out of the last 7 times. Odds are the ball will land on black. The player then doubles the last bet and bets \$20 on black. Again, red. Now 7 out of 8 times. The player then doubles the last bet and bets \$40 on black. Finally the ball lands on black. The player has won a total of \$10.

I suppose this could be expanded to include looking at color, columns, odd or even numbers, etc. I don't imagine one could get rich on one spin, but over the course of several spins and very deep pockets, I think the end result would be that the player would come out winning.

103 posted on 01/08/2004 11:10:13 AM PST by new cruelty ("But there are also unknown unknowns — the ones we don't know we don't know." You know?)

To: 303george
"... The player has won a total of \$10. "

Actually... I am not sure what the return is on just placing a bet on odd or even... so perhaps the amount won is greater than \$10.

106 posted on 01/08/2004 11:13:38 AM PST by new cruelty ("But there are also unknown unknowns — the ones we don't know we don't know." You know?)

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