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1 posted on 05/07/2015 7:27:31 AM PDT by MNDude
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To: MNDude

“I’m trying to figure something out for work, but my math skills are not very good. How do I calculate percentages if an event reoccurs multiple times?

Suppose there is an event that has the chance of occurring on in 6 times (like rolling a dice and getting a “five”).

What are the chances I will get a “five” if I roll the dice six times?”

If the rolls are independent and by “get a five” you mean you will get at least one five then the answer is:

1-(5/6)^6 which is the probability of the complement of getting no fives.

If the rolls are independent and by “get a five” you mean you will exactly one five then the answer is:

6*((1/6)*(5/6)^5)= (5/6)^5 which 6 times the probability of getting just one five on any specific roll.


56 posted on 05/07/2015 10:04:22 AM PDT by Catphish
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To: MNDude

Are you rolling one die six times or a pair of dice six times?

If its a pair of dice, there are 36 total possible combinations in the first roll, only four of which will add up to ‘five’.

Your odds of getting a ‘five’ in that first roll are 4/36 or 11.1 percent.

Your odds of getting a ‘five’ in each subsequent roll are the same.

Your odds of getting at least one ‘five’ after six rolls are 24/36 or 66.67 percent.


59 posted on 05/07/2015 11:56:39 AM PDT by chopperman
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To: MNDude

Depends on what factors control the situation you want to predict.


60 posted on 05/07/2015 11:58:22 AM PDT by A CA Guy ( God Bless America, God Bless and keep safe our fighting men and women.)
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